Prepare for the second stage of testing

Typical problems

Correlated subqueries sometimes let to create the query very briefly, which can look more cumbersome when you use other means. We shall remind that correlated subquery contains reference to the query which it contains (we shall name it the main query) with the result that subquery executes for each string of the main query.

Example 8.9.1

It is required to determine the date and the flights of every passenger, committed by them at its last flight day

To say the other way, you have to find the maximum dateof the flight for each passenger and to find all of his flights. With determination of the maximum date there is no problems :

Console

Execute

SELECT id_psg, MAX(date) 
FROM pass_in_trip
GROUP BY id_psg;

SELECT id_psg, MAX(date) FROM pass_in_trip GROUP BY id_psg;

    Scheme

No scheme

However, there is no flight. If we'll try to include flight in the list of output:

Console

Execute

SELECT id_psg, trip_no, MAX(date) 
FROM pass_in_trip
GROUP BY id_psg;

SELECT id_psg, trip_no, MAX(date) FROM pass_in_trip GROUP BY id_psg;

    Scheme

No scheme

Console

Execute

SELECT id_psg, trip_no, MAX(date) 
FROM pass_in_trip
GROUP BY id_psg, trip_no;

SELECT id_psg, trip_no, MAX(date) FROM pass_in_trip GROUP BY id_psg, trip_no;

    Scheme

No scheme

Console

Execute

SELECT id_psg, trip_no, [date] 
FROM pass_in_trip pt_1
WHERE [date] = (SELECT MAX([date]) 
 FROM pass_in_trip pt_2 
 WHERE pt_1.id_psg = pt_2.id_psg
 );

SELECT id_psg, trip_no, [date] FROM pass_in_trip pt_1 WHERE [date] = (SELECT MAX([date]) FROM pass_in_trip pt_2 WHERE pt_1.id_psg = pt_2.id_psg );

    Scheme

No scheme

Here for each flight it is checked, whether it is accomplished last flight day of the given passenger. Thus if such flights there was a several, we receive all of them.

Seeming lack of the resulted solution is just also that the subquery should be calculated for every string of main query. To avoid it, it is possible to offer the alternative solution, which is using joining of the Pass_in_trip table with a subquery resulted at the beginning which calculates the maximal dates for each passenger:

Console

Execute

SELECT pt_1.id_psg, trip_no, [date] 
FROM pass_in_trip pt_1 JOIN 
 (SELECT id_psg, MAX([date]) md 
 FROM pass_in_trip 
 GROUP BY id_psg
 ) pt_2 ON pt_1.id_psg = pt_2.id_psg AND 
 [date] = md;

SELECT pt_1.id_psg, trip_no, [date] FROM pass_in_trip pt_1 JOIN (SELECT id_psg, MAX([date]) md FROM pass_in_trip GROUP BY id_psg ) pt_2 ON pt_1.id_psg = pt_2.id_psg AND [date] = md;

    Scheme

No scheme

However, as it will seem strangely, optimizer of the  A database management system (DBMS) by Microsoft Corporation. SQL(Structured Query Language) is a database computer language designed for the retrieval and management of data in relational database management systems (RDBMS), database schema creation and modification, and database object access control management.SQL Server 2000 will choose for both queries the identical  execution plan at presence of a natural index (cluster) on a primary key. Accordingly, and time of execution of queries should not differ.

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