21:53

	Content	Login

SQL Problems and solutions S. I. Moiseenko

Content

SQL console

back go forward

Common mistakes in solving SELECT statement exercises

Database «Airport»

Exercise 93

For each company, find time the company's planes have spent during accomplished flights. Result set: company name, time in minutes.

The issue with this exercise may be illustrated by a message of one of our participants:

Console

Execute

SELECT Trip.time_out, Trip.time_in
       FROM Trip
       WHERE Trip.id_comp=2;

time_out	time_in
1900-01-01 09:35:00.000	1900-01-01 11:23:00.000
1900-01-01 17:55:00.000	1900-01-01 20:01:00.000

It turns out that the company Aeroflot has made two flights, the first one has flight time of 1 hour 48 minutes, the second one - 2 hour 6 minutes, The total duration of flights turns out (108 + 126) = 234 minutes, but not is 216 minutes (as it is specified in "correct result ").

Misunderstanding is caused by insufficient studying of the description and the scheme of database. Trip table represents the schedule of flights, which are carried out daily.

The information on flights of passengers contains in Pass_in_trip table. Let's look what flights of the company with id_comp=2 have been carried out:

Console

Execute

SELECT pt.trip_no, date, time_out, time_in
       FROM pass_in_trip pt 
       JOIN
       (SELECT trip_no,time_out,time_in FROM trip WHERE id_comp=2) t
               ON t.trip_no=pt.trip_no 
       GROUP BY pt.trip_no, date, time_out, time_in;